Unit 6 Radical Functions Homework 8 Inverse Relations And

$$f^{-1}(x) = x^2 - 3$$

Now, isolate $y$ by subtracting 3. $$x^2 - 3 = y$$ Unit 6 Radical Functions Homework 8 Inverse Relations And

Subtract 4 from both sides: $$x - 4 = 2y$$ Divide by 2: $$\frac{x - 4}{2} = y$$ $$f^{-1}(x) = x^2 - 3$$ Now, isolate $y$ by subtracting 3

$$f^{-1}(x) = \frac{x - 4}{2} \quad \text{or} \quad f^{-1}(x) = \frac{1}{2}x - 2$$ The Radical Connection: Why Unit 6 Matters This specific homework assignment usually introduces the interplay between radicals and exponents . This is where the "Radical Functions" part of the unit title comes into play. $$f^{-1}(x) = x^2 - 3$$ Now